Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
The area of the composite figure can be found by summing the whole area that made up the figure. Therefore, the area of the figure is 213.5m²
<h3>Area of a composite figure</h3>
The area of the composite figure is the sum of the area of the whole figure.
Therefore, the composite figure can be divided into 2 triangles and two rectangles.
Hence,
area of triangle1 = 1 / 2 × 10 × 13 = 65 m²
area of the triangle2 = 1 / 2 × 15 × 7 = 52.5 m²
area of the rectangle1 = 8 × 3 = 24 m²
area of rectangle2 = 7 × 6 = 42 m²
area of rectangle3 = 5 × 6 = 30 m²
Therefore,
area of the composite figure = 65 + 52.5 + 24 + 42 + 30 = 213.5 meters squared
learn more on area here: brainly.com/question/27744042
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Answer:
Step-by-step explanation:
x/7 - 13 ≥ -11
x/7 ≥ 2
x ≥ 14
m/-6 + 16 ≥ 19
m/-6 ≥ 3
m/6 ≤ -3
m ≤ -18
Area of triangle = 1/2 × base × height
so,
24=1/2*base*4
base=12m
Answer:
y=2
Step-by-step explanation: