Question

I'm not sure what I'm doing wrong in simplifying this square root. I'm factoring out 32 which is 2x2x2x2x2, In this there is 1 set of 5 so I thought the answer would be 1. However, my calculator is telling me its the answer is 2. What did I do wrong?
$\sqrt[5]{32}$

Answer 1

Answer:

see explanation

Step-by-step explanation:

note that $2^{5}$ = 2 × 2 × 2 × 2 × 2 = 32, hence

$\sqrt[5]{32}$ = $\sqrt[5]{2^{5} }$ = $(2^{5})^{\frac{1}{5} }$ = $2^{1}$ =  2

Answer 2

Answer:

2

Step-by-step explanation:

note that 2^{5} = 2 × 2 × 2 × 2 × 2 = 32, hence

\sqrt[5]{32} = \sqrt[5]{2^{5} } = (2^{5})^{\frac{1}{5} } = 2^{1} =  2