Given a polynomial f(x), if (x - 1) is a factor, what else must be true?

Mathematics

2 answers:

Novosadov [1.4K]4 years ago

8 0

F(0) = 1 must be true
<span>If x=1,
f(1)=(1-1)*g(1)=0*g(1)=0
So, you get that f(1)=0 is true.
</span>hope this helps

kozerog [31]4 years ago

6 0

Answer:

$f(1)=0$

Step-by-step explanation:

we know that

If $(x-1)$ is a factor of the polynomial f(x)

then

For $x=1$

the polynomial must be equal to zero

$f(1)=0$

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Naddika [18.5K]

Answer:

6.3°

Step-by-step explanation:

$\because \: \pi^{c} = 180 \degree \\ \\ \therefore \: 1^{c} = \frac{180 \degree }{\pi} \\ \\ \therefore \: 0.11^{c} = \frac{180 \degree }{3.14} \times 0.11 \\ \\ \therefore \: 0.11^{c} = \frac{180 \degree }{314} \times 11 \\ \\ \therefore \: 0.11^{c} = \frac{1980 \degree }{314} \times 11 \\ \\ \therefore \: 0.11^{c} = 6.30573248\degree \\ \\ \huge \red{ \boxed{\therefore \: 0.11^{c} = 6.3\degree }} \\ \\$

8 0

4 years ago

In a designated VIP seating section there must be an odd number of seats in each row and each row must have two more seats than

Vikki [24]

Let n be the total number of rows and there are x seats is the 1st row where x is an odd natural number.

As each row must have 2 more seats than the one before it, so

Number of seats in 2nd row = x+2

Number of seats in 3rd row = x+2+2=x+2x2

Number of seats in 4th row = x+2+2+=x+2x3

Similarly, the number of seats in (n-1)th row =x+2x(n-1)

the number of seats in n^{th} row, i.e last row =x+2x n.

As the front row must have one-quarter of the total seats in the back 2 rows combined, so

$x =\frac 1 4 ( x+2\times(n-1) + x+2\times n) \\\\\Rightarrow 4x=2x+4n-6 \\\\\Rightarrow 4x-2x=4n-6 \\\\\Rightarrow 2x=4n-6 \\\\\Rightarrow x=2n-3\cdots(i)$