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3 years ago

There is a cube that is 1 unit long, 1 unit wide,

Mathematics

2 answers:

Svetllana [295]3 years ago

6 0

Answer:

answer is 1 cubic unit

hope this helps

Nikitich [7]3 years ago

4 0

Answer:

v = 1

Step-by-step explanation:

volume of a cube = side cubed

1 cubed = 1

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A company offers a raffle whose grand prize is a $35,000 new car. Additional prizes are a $1,100 television and $600 computer. T

anastassius [24]

Answer:

-$ 10.13

Step-by-step explanation:

Given,

The cost price of each ticket = $ 22,

So, the value of each ticket other than price ticket = - $ 22, ( negative sign shows loss,i.e. if we don't get the price we will have the loss of $ 22 )

Now, there are 3 tickets in which first is of $35,000 price, second is of $1,100 and third is of $ 600,

So, the value of first ticket = 35000 - 22 = $ 34978,

Value of second ticket = 1100 - 22 = $ 1078,

Value of third ticket = 600 - 22 = $ 578,

Also,

$\text{Probability}=\frac{\text{Favourable outcome}}{\text{Total outcome}}$

Hence, by the above information we can make a table for the given situation,

Number 2997 1 1 1

Price -$ 22 $ 34978 $ 1078 $ 578

Probability 2997/3000 1/3000 1/3000 1/3000

Therefore, the expected value of a ticket

$=-22\times \frac{2997}{3000}+34978\times \frac{1}{3000}+578\times \frac{1}{3000}$

$=-$10.126$

≈ - $ 10.13

5 0

3 years ago

How do you solve this?

geniusboy [140]

Hello from MrBillDoesMath!

Answer:

x = 50

Discussion:

(4x +5) ( 2x - 2) = 8x^2 - 8x + 10x - 10

= 8x^2 + 2x - 10 (A)

(16x^8)/(2x^6) + 90 = 8x^2 + 90 (B)

Setting (A) = (B) gives

8x^2 + 2x - 10 = 8x^2 + 90

Subtract 8x^2 from both sides:

2x - 10 = 90

Add 10 to both sides:

2x = 90 + 10 = 100

Divide both sides by 2:

x = 100/2 = 50

Thank you,

MrB

8 0

3 years ago

Please help me solve for x

Elena-2011 [213]

Answer:

$x=49^o$

Step-by-step explanation:

We know that we are dealing with parallel lines, as there are double headed arrows on each of the lines, pointing in the same direction.

This means we can use corresponding / alternate angle laws.

We know that the angles on a straight line add up to $180^0$ , so we can solve for the angle just above the $131^o$ to try and see if that will help us.