From the 64 values in the table on the left, count how many fall within the given ranges under the "classes" column in the table on the right. The "frequency" is the number of values in the data that belong to a given "class".
For example, "< -16.0" means "values below -16.0". Only one number satisfies this: -16.2 (first row, third column). So the frequency for this class is just 1.
Then for the range "-15.9 - 13.0", which probably means "numbers between 15.9 and -13.0, inclusive", the frequency is 0 because every number in the table is larger than the ones in this range.
And so on.
Answer:
5^1 in expended from is 5
hope it helps.
Answer:
use the distributive property to distribute the 8
-16+16n+3n=40+5n
-16+19n=40+5n
-16=40+5n-19n
-16=40-14n
-14n+40= -16
-14n= -16-40
-14n= -56
n= -56/-14
n= 4
30 in each bus. 17 in each van
To solve this problem, we first have to create a system of equations. After that, you set the equations equal to each other, and use that to simplify and find the value of one variable. Once that is found that answer can be plugged into one of the two original equations to find the other variable.