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Umnica [9.8K]
2 years ago
14

Find the relationship between zeros and intercepts of the polynomial m2 + 5m + 4.

Mathematics
1 answer:
irina1246 [14]2 years ago
5 0

The zeros and intercepts of the polynomial m^2 + 5m + 4 will be different.

<h3>Intercepts and zero of a function</h3>

A quadratic function is a function that has a degree of 2.

Given the following equation

f(m) = m^2 + 5m + 4

The x-intercept occurs at the point where f(m) is zero and same is applicable to the zeros of the function.

This shows that the zeros and intercepts of the polynomial m^2 + 5m + 4 will be different.

Learn more on intercepts here: brainly.com/question/1884491

#SPJ1

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Haroldo, Xerxes, Regina, Shaindel, Murray, Norah, Stav, Zeke, Cam, and Georgia are invited to a dinner party. They arrive in a r
alexira [117]

Answer: The probability is P = 0.056

Step-by-step explanation:

The invited ones are:

Haroldo, Xerxes, Regina, Shaindel, Murray, Norah, Stav, Zeke, Cam, and Georgia

So we have a total of 10 persons.

The case where Xerxes arrives first and Regina arrives last is:

We have 10 slots, each slot corresponds to who arrived in which time.

For the first slot we have only one option, this is Xeres.

For the next slot we have 8 options (because Xeres already arrived, and Regina must arrive at last)

For the next slot we have 7 options.

for the next one we have 6 options, and so on.

So the combinations are:

C = 1*8*7*6*5*4*3*2*1*1 = 40320

Now, the total number of combinations is:

for the first slot we have 10 options, for the second we have 9 options and so on.

c = 10*9*8*7*6*5*4*3*2*1 = 725760

The probability is the combinations where Xerxes arrives first and Regina rrives last divided the total number of probabilities.

P = C/c = 0.056

7 0
3 years ago
I don't know what to write! Help me please​
Andrews [41]
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3 0
3 years ago
The relationship (3,2)(2,5) (8,5) (3,6) is a function<br> A True<br> B) False
ryzh [129]

Answer:

I would say it's B. false

6 0
2 years ago
Read 2 more answers
A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title
kirill [66]
y' = \frac{dy}{dx}

seperable differential equations will have the form
\frac{dy}{dx} = F(x) G(y)

what you do from here is isolate all the y terms on one side and all the X terms on the other
\frac{dy}{G(y)} = F(x) dx
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
\int \frac{1}{G(y)} dy = \int F(x) dx&#10;&#10;

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it


In your problem,
G(y) = \sqrt{1-y^2}&#10;&#10;F(x) = 2x

so all you need to integrate is
\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx
5 0
3 years ago
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love history [14]
It would be D hope this helps
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