Answer:
x = 1/21
Step-by-step explanation:
7 = 3/9x
Multiply both sides by 9x
7 x 9x = 3/9x x 9x
9x cancels out on the right side
63x = 3
Divide both sides by 63 to isolate x
63x/63 = 3/63
x = 1/21
Answer:
length= 9
width= 3
Step-by-step explanation:
x= width
length = x+6
x+6+x+6+x+x=24
4x+12=24
take 12 from both sides
4x= 12
x=3
Answer: 4%-16000 and 9.5%-30000
Why:
1) x+y=46000
x=46000-y
2) 4%x+9,5%y=3490;
4x + 9.5y=349000; so 4*(46000-y)+9.5y=349000;
5.5y=165000
y=30000
x=46000-30000=16000
Answer:
plz help and this is fro khan academy if it helps!
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Step-by-step explanation:
plz help and this is fro khan academy if it helps!
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Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be

Hence, the mean and standard deviation are 567.2 and 89.88 resp.