Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
A = 2+3a +6
a-3a = 8
-2a = 8
a = -8/2 = -4
99
/ \
11 9
/ \
3 3
165
/ \
33 5
/ \
3 11
GCF=3
Answer:
Step-by-step explanation:
x+165 = 180
x = 180 - 165
x = 15