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3 years ago

1. Find the slope of a line that passes through the points (-1,-4) and (5, -1).

1 answer:

7 0

The answer is A. 1/2

(-1,-4) are (x1, y1)
(5,-1) are (x2, y2)
So you subtract y2-y1/x2-x1 = -1-(-4)/5-(-1)
-1-(4) = 3
5-(-1) = 6
3/6= 1/2
Slope is 1/2 making A your answer

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X equals 10, Y equals -2, and Z equals -5 what is x divided by y

Aleks04 [339]

X = 10
y = -2

x/y = 10/-2
x/y = -5

Hence, x/y = z

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3 years ago

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What is a solution to x ≥ 20

Triss [41]

Answer:

Step-by-step explanation:

Any number equal to or greater than 20 is a solution. 22 would be a solution.

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3 years ago

12) Josh has $252 in his bank account. This is $12 more than 6 times the amount of money

OLga [1]

Answer:

Step-by-step explanation:

(252-12)/6=40

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3 years ago

The coordinates of A and B are (3k, 8) and (k, -3) respectively. Given that the gradient of the line segment AB is 3, find the v

Vladimir [108]

Step-by-step explanation:

gradient = slope or several other words.

it describes how strongly a line (or tangent to a bent curve) is going up or down or ... if it is changing at all.

it is represented by the ratio

(y coordinate change / x coordinate change)

when going from one point on the line to another.

in our case, when going from A to B we have

x changes by -2k (from 3k to k).

y changes by -11 (from 8 to -3).

so, the gradient or slope is

-11/-2k = 3

11/2k = 3

11 = 3×2k = 6k

k = 11/6

A = (33/6, 8) = (11/2, 8)

B = (11/6, -3)

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2 years ago

A manufacturer produces bolts of a fabric with a fixed width. A quantity q of this fabric (measured in yards) that is sold is a

BigorU [14]

Answer:

$R'(20) = 2000$

Step-by-step explanation:

We are given the following in the question:

Quantity, q

Selling price in dollars per yard, p

$q=f(p)$

Total revenue earned =

$R(p)=pf(p)$

f(20)=13000

This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.

f′(20)=−550

This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.

We have to find R'(20)

Differentiating the above expression, we have,

$R'(p) = \displaystyle\frac{d(R(p))}{dp} = \frac{d(pf(p))}{dp} = f(p) + pf'(p)$

Putting the values, we get,

$R'(p) = f(p) + pf'(p)\\\\R'(20) = f(20) + 20(f'(20))\\\\R'(20) = 13000 + 20(-550) = 2000$

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3 years ago