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nlexa [21]
3 years ago
10

a recipe makes a total of 5 cups a serving of pudding is 3/4 cup how many servings of pudding does the recipe make?

Mathematics
1 answer:
klasskru [66]3 years ago
4 0
The recipe makes Zero
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What is a bird favorite type math
Dimas [21]

Answer:

word problems

Step-by-step explanation:

A random guy made 100 bird houses and each bird house has 100 seeds how many seeds are there in total 100,000

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3 years ago
Find the value(s) of x where the tangent to the graph of y=e^5x is parallel to the
Alik [6]

Answer:

There are none.

Step-by-step explanation:

<u>No calculus involved:</u>

The line, in slope-intercept form, has equation y=-10x+17, ie is always decreasing (easy to spot applying the definition)

Meanwhile, y=e^{5x} is always increasing over its domain.

At no point the tangent will be decreasing.

<u>Let's use calculus</u>

We are to solve the equation y'(x) = -10 \rightarrow 5e^{5x} = -10 \rightarrow e^{5x}=-2 which has no real solutions.

8 0
2 years ago
1/4 Divided by 16 3/4 (Detailed, worked out answer please)
scZoUnD [109]
14 would probably be the answer idk
8 0
3 years ago
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Steve and Abby purchased a set of vases to place on a 12 foot long mantel above their fireplace. They want to place one vase 1/4
Nonamiya [84]

Answer: One vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

Step-by-step explanation:

You know that lenght of the mantel above their fireplace is 12 feet.

They want to place one vase \frac{1}{4} of the distance from one end of the mantel. This distance in feet is:

distance_{vase1}=(12feet)(\frac{1}{4})\\\\distance_{vase1}=3feet

 They want to place the other vase \frac{3}{4} of the distance from the same end of the mantel. Therefore, this distance in feet is:

distance_{vase2}=(12feet)(\frac{3}{4})\\\\distance_{vase2}=\frac{36feet}{4}\\\\distance_{vase2}=9feet

Therefore, one vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

5 0
3 years ago
Quadrilateral ABCD is the result of a translation of quadrilateral EFGH. Segment EF is parallel to segment HG in the pre-image.
Mazyrski [523]
The correct answer:
The corresponding segments BC and AD in the image are parallel
3 0
3 years ago
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