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fenix001 [56]
3 years ago
7

Which inequality is represented by this graph?

Mathematics
1 answer:
solniwko [45]3 years ago
6 0

Answer:

D) y> -\frac{1}{6} x +1

Step-by-step explanation:

It's going up so it has to be greater than sign, and it's dotted

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-8x+4y=28 solve for y
olga55 [171]
This is how I would do it:
-8x=28-4y divide the entire equation by 4
-2x=7-y Put y back on the left and put x on the right 
y=7-2x.
8 0
3 years ago
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Andy has a collection of movie dvds. in andys collection 3/5 of the dvds are action 1/4 of the dvds are comedy. andy said that 4
Lerok [7]
If 3/5 are action and 1/4 are comedy then:

(3/5)+(1/4) are action or comedy

To add/subtract fractions you need a common denominator...

(3/5)*(4/4)+(1/4)(5/5)

(12/20)+(5/20)

17/20

So 17/20 (85%) of his collection are action or comedy not 4/9...


4 0
3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
AlekseyPX
I think you need to add them up and u will get 27
5 0
3 years ago
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A rectangle has a length of 3x + 7 and a width of 2x. If the perimeter of the
Art [367]

Answer:

The length of the rectangle is 31.

Step-by-step explanation:

We have that the length (L) and width (W) are:

L = 3x + 7

W = 2x

The perimeter of the rectangle is given by:

P = 2W + 2L

94 = 2(2x + 3x + 7)

94 = 10x + 14

x = 8

Now, we can calculate the length of the rectangle:

L = 3x + 7 = 3*8 + 7 = 31        

         

Therefore, the length of the rectangle is 31 units.

I hope it helps you!                

7 0
3 years ago
Question is in the pictures.
Kipish [7]
<h3>Answer:</h3>

x/tan(x) is an even function

sec(x)/x is an odd function

<h3>Explanation:</h3>

<em>x/tan(x)</em>

For f(x) = x/tan(x), consider f(-x).

... f(-x) = -x/tan(-x)

Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...

... f(-x) = -x/(-tan(x)) = x/tan(x) = f(x)

The relation f(-x) = f(x) is characteristic of an even function, one that is symmetrical about the y-axis.

_____

<em>sec(x)/x</em>

For g(x) = sec(x)/x, consider g(-x).

... g(-x) = sec(-x)/(-x)

Now, we know that sec(x) is an even function, so sec(-x) = sec(x). Using this, we have ...

... g(-x) = sec(x)/(-x) = -sec(x)/x = -g(x)

The relation g(-x) = -g(x) is characeristic of an odd function, one that is symmetrical about the origin.

6 0
3 years ago
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