Question

Yuron is sketching a scale drawing of a famous painting. The painting is 54 inches wide and 72 inches long. He used a scale factor of Two-thirds to make his sketch. How many inches wide is Yuron’s sketch?

Answer 1

Answer:

Yuron's painting is 36 inches wide.

Step-by-step explanation:

Given that Yuron is sketching a scale drawing of a famous painting which is 54 inches wide and 72 inches long. He used a scale factor of $\frac{2}{3}$ to make his sketch.

We are given to find the width of Yuron’s sketch.

Let, w and w' represents the width of the famous painting and  Yuron's painting.

Then, w = 54 inches,  w' = ?

We know that the scale factor is defined by

$S=\frac{Length of a side of a dilated figure}{Length of the corresponding side of the original figure}$

Therefore, we have

$\frac{2}{3} =\frac{Width og Yuron's painting}{Width of the famous painting}$

$\frac{2}{3} = \frac{w}{w}$

$\frac{2}{3}=\frac{w}{54}$

$\frac{2}{3}=\frac{2*54}{3}$

$w= 36$

Thus,  Yuron's painting is 36 inches wide.

Answer 2

Answer:

Yuron's painting is 36 inches wide.

Step-by-step explanation: