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yaroslaw [1]
3 years ago
5

What is another way to express 52+24

Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0
50 plus2 plus 20 plus 4
andrew-mc [135]3 years ago
6 0

Answer:

4(13+6) = 76

hope this helps :D

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Find the area of a sector with a central angle of 102 degrees and a radius of 15.7 millimeters.
Stella [2.4K]
A = .5 r^2 theta
Theta must be in radians
A = .5 (15.7)^2 (102)(pi/180)
A= 219 mm^2
8 0
3 years ago
for every five baseball cards that Mickey has Mike has 3 baseball cards if Mike has 72 baseball cards how many cards does Mickey
Otrada [13]
70. Mike has 70 cards

3 0
3 years ago
Two bicyclists ride in opposite directions. The speed of the first bicyclist is 5mph faster than the second. After 2 hours they
kirza4 [7]

Answer:

A. 15 mi/h; 20 mi/hr

Step-by-step explanation:

3 0
1 year ago
How do I use the following cosine equation to get the Sinusoid Max & Min Times (x values), and Sinusoid Max and Min Values (
Paraphin [41]

9514 1404 393

Answer:

  • maximum: (x, y) = (12.4n+3.2, 186.322)
  • minimum: (x, y) = (12.4n+9.4, 163.498)

Step-by-step explanation:

You know that cos(α) is a maximum at α=0, 2π, 4π, and all even multiples of π. You know cos(α) is a minimum for α=π, 3π, 5π, and all odd multiples of π.

You can find your value of x at which y will be a maximum by setting the argument of the cosine function equal to zero (and/or 2nπ). If we use α=2nπ, then we have ...

  α = (5π/31)(x -3.2) = 2nπ

  (x -3.2) = (31/5)(2n) = 12.4n

Tidal maxima will occur at ...

 x = 12.4n +3.2 . . . . . for integer values of n

Without bothering to go through the solution for α being odd multiples of π, we can see from this that the period is 12.4 hours. We know the tidal minimum  will be half a period later, or 6.2 hours later than this.

Tidal minima will occur at ...

  x = 12.4n +9.4 . . . . for integers n

__

Of course, cos(α) has extremes of ±1, so your tidal maximum will be ...

  y = 11.412 +174.91 = 186.322

and your tidal minimum will be ...

  y = -11.412 +174.91 = 163.498

4 0
3 years ago
Look at question attatched
Ratling [72]

Answer:

If the discs were measured to the nearest milimetre, it might be possible, that they are actually 1.64cm wide instead of only 1.64cm as shown.

Therefore the box would fill up much quicker and there will not be enough space.

Step-by-step explanation:

1.6cm * 16 discs = 25.6cm (would fit)

1.64cm * 16 discs = 26.24cm (would not fit)

5 0
3 years ago
Read 2 more answers
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