Answer:
A. {x,y}={-2,-3}
// Solve equation [2] for the variable x
[2] x = 2y + 4
// Plug this in for variable x in equation [1]
[1] (2y+4) - y = 1
[1] y = -3
// Solve equation [1] for the variable y
[1] y = - 3
// By now we know this much :
x = 2y+4
y = -3
// Use the y value to solve for x
x = 2(-3)+4 = -2
B. [1] 3x=3y-6
[2] y=x+2
Equations Simplified or Rearranged :
[1] 3x - 3y = -6
[2] -x + y = 2
Solve by Substitution :
// Solve equation [2] for the variable y
[2] y = x + 2
// Plug this in for variable y in equation [1]
[1] 3x - 3•(x +2) = -6
[1] 0 = 0 => Infinitely many solutions
C.Step by Step Solution
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System of Linear Equations entered :
[1] 4x - y = 2
[2] 8x - 2y = 4
Solve by Substitution :
// Solve equation [1] for the variable y
[1] y = 4x - 2
// Plug this in for variable y in equation [2]
[2] 8x - 2•(4x-2) = 4
[2] 0 = 0 => Infinitely many solutions
Answer:
Rs. 23520
Step-by-step explanation:
Given that :
At 12% profit ; sales price = 18,816
At (12 + 3)% profit ; sales price = x
Hence,
0.12 = 18,816
0.15 = x
Cross multiply ;
0.12x = 0.15 * 18816
0.12x = 2822.4
x = 2822.4 / 0.12
x = 23520
Hence, sales price for a 3% increaa in profit should be Rs. 23520
With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.
With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.
1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.
P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13
So the answer is B.
Answer: 390 miles
Step-by-step explanation:
Reggie ran for half an hour in the morning and half an hour in the evening.
That is a total of 1 hour for the day.
He runs 6.5 miles in one hour.
In 60 days he would have ran;
= 60 * 6.5
= 390 miles
Answer:
13x^8 + 4x^5 - 16x^2
Step-by-step explanation:
Standard form is just rearranging each group of numbers so that the group with the most exponents on the variables is at the beginning. So it's basically least to greatest but with exponents. Hope this helped!