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shtirl [24]
4 years ago
5

Evaluate. 43⋅(10025)−50 Enter your answer in the box.

Mathematics
2 answers:
Lorico [155]4 years ago
8 0

The answer to the question is 431,025.

geniusboy [140]4 years ago
7 0

Hi!

<h3>Let's use PEMDAS to solve this. </h3>
  • Multiplication

43 * 10025 - 50

431075 - 50

  • Subtraction

<u>431025</u>

<h2>The answer is 431075</h2>

Hope this helps! :)

-Peredhel

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Help me please I have no clue
Lynna [10]

Answer:

Step-by-step explanation:

You see that there’re angles with 30 and 90 degrees that means that -> 180-(90+30)=60 (measurement of the third angle)

Here you’ll need to use the 30,60,90 degree triangle rule:

The opposite side of 30 degree will be y

30->y

90->2y->12√3 => y=6√3

60->y√3->x => 6√3x√3=6x3=18

To understand the rule better you can check the picture below.Wish it will help you!Good luck!

8 0
3 years ago
The pulse rates of 174 randomly selected adult males vary from a low of 39 bpm to a high of 111 bpm. Find the minimum sample siz
Daniel [21]

Answer:

a. The sample size is approximately 97 adults

Step-by-step explanation:

The given parameters are;

The number of adults surveyed, n = 174

The lowest value of the pulse rate = 39 bpm

The highest value of the pulse rate = 111 bpm

The level of confidence used for determining the sample size = 90%

The given sample mean = 3 pm of the population mean

a. The range rule of thumb states that the standard deviation is approximately one quarter (1/4) of the range

The range = 111 bpm - 39 bpm = 72 bpm

Therefore, the standard deviation, σ = 72 bpm/4 = 18 bpm

The sample size, 'N', is given as follows;

N = \dfrac{z^2 \cdot p \cdot q}{e^2}

Where;

N = The sample size

z = The confidence level, 90% (z-score at 90% = 1.645)

p·q = σ² = 18² = 324

e² = 3² = 9

N = \dfrac{1.645^2  \times 324}{3^2} = 97.4169

Therefore the appropriate sample size, N ≈ 97 adults.

8 0
3 years ago
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4 years ago
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seropon [69]

You are right. 5 is correct.

6 0
3 years ago
The data in the table shows a sinusoidal relationship between the number of seconds an object has been moving and its velocity
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Answer:

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