Question

Determine the volume of the figure that has a radius of 2 feet. Round your answer to nearest tenth of a cubic foot ​

Answer 1

Answer: 138.2 ft³

Step-by-step explanation:

The area of the figure is:

$V_f=V_{cylinder}+V_{cone}$

Calculte the volume of the cylinder:

$V_{cylinder}=hr^2\pi$

Where r is the radius ($r=2ft$) and h is the height.

Then:

$V_{cylinder}=(10ft)(2ft)^2\pi=125.66ft^3$

 Calculte the volume of the cone:

$V_{cone}=\frac{1}{3}hr^2\pi$

 Where r is the radius ($r=2ft$) and h is the height.

Then:

$V_{cone}=\frac{1}{3}(3ft)(2ft)^2\pi=12.56ft^3$

Therefore:

$V_f=125.66ft^3+12.56ft^3=138.2ft^3$