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3 years ago

9

ILL GIVE YOU BRAINLEST PLEASE THIS IS THE ONLY QUESTION I HAVENT ANSWER!

1 answer:

Alona [7]3 years ago

6 0

A and B

Both A and B, when simplified get -(1/6), because the others have either 0 or 2 negative signs, denoting a positive end result.

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WILL MARK BRAINLIST!!What is the measure of one interior angle in a regular pentagon?

never [62]

The answer is 108°

A regular pentagon has all its five sides equal and all five angles are also equal. Hence, the measure of each interior angle of a regular pentagon is given by the below formula. Measure of each interior angle = [(n – 2) × 180°]/n = 540°/5 = 108°.

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2 years ago

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melomori [17]

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Area: 9*8= 72 ft²

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3 years ago

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Answer the equation according to the directions

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4 years ago

Round to the nearest ten thousand.<br> 532,413

8_murik_8 [283]

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3 years ago

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Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P

Fed [463]

Answer:

Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2) The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

<u><em>The question is</em></u>

Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute

Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan

Part 1)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

$3x+100$

<em>Cost Plan B</em>

$5x$

we know that

In order for plan A to be cheaper than plan B, the following inequality must hold true.

cost of plan A < cost of plan B

substitute

$3x+100 < 5x$

solve for x

subtract 3x both sides

$100< 5x-3x\\100$

divide by 2 both sides

$50 < x$

Rewrite

$x> 50\ min$

therefore

The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

$3x+100$

<em>Cost Plan B</em>

$5x$

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

$3x+100= 5x$

solve for x

$5x-3x=100\\2x=100\\x=50\ min$

therefore

The number of minutes in a month must be equal to 50 minutes

5 0

3 years ago