Answer:
Length = 11
Width = 6
Step-by-step explanation:
We know that the length is x and the width is x - 5 since it is 5 less than the length.
The equation to find the perimeter of a rectangle is 2w + 2l
We will plug in the values and solve
2(x-5) + 2(x) = 34
2x - 10 + 2x = 34
4x - 10 = 34
4x = 44
x = 11
Since the length is simply x, we know that it is 11. We subtract 5 to find the width.
11 - 5 = 6.
The width is 6.
Answer:
Should be C
Step-by-step explanation:
Only the same power number can be use to add or subtract :)
But why is A, B and C same kinda stuff?
Answer:
The mean is 24.205
Step-by-step explanation:
Firstly, we need to get the z-score
From the question, the probability we have is the probability that commuters take more than 22 minutes to commute one-way
So the probability we had was;
P( x > 22)
So we need the z-score corresponding to 63.70% or simply 0.637
We can use the standard normal distribution table to get this
Mathematically, from the standard normal distribution table this is -0.35
z-score = (x- mean)/SD
-0.35 = (22-mean)/6.3
22-mean = -2.205
mean = 22 + 2.205 = 24.205
Answer:
? = 13.6
Step-by-step explanation:
Let unknown angle be x
so
tan x = p/b
tan x = 8/33
x =tan‐¹(8/33)
or, x = 13.62699486
so, x = 13.6
Using the normal distribution, it is found that 0.0329 = 3.29% of the population are considered to be potential leaders.
In a <em>normal distribution</em> with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 550, hence
.
- The standard deviation is of 125, hence
.
The proportion of the population considered to be potential leaders is <u>1 subtracted by the p-value of Z when X = 780</u>, hence:
has a p-value of 0.9671.
1 - 0.9671 = 0.0329
0.0329 = 3.29% of the population are considered to be potential leaders.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213
