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blagie [28]
3 years ago
13

I need this ASAP. Pls help

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

answer is below. you can use photo math

Step-by-step explanation:

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Solve for x: 1 over 4 (2x − 14) = 4. 15 15 over 2 9 11
zloy xaker [14]
1/4(2x - 14) = 4....multiply both sides by 4
2x - 14 = 4 * 4
2x - 14 = 16
2x = 16 + 14
2x = 30
x = 30/2
x = 15 <==
3 0
3 years ago
Read 2 more answers
Bruce has a bottle that contains 60% of lemon juice and the rest water. The bottle has 1 liter of water.
dlinn [17]
Part A :
x - the total amount of liters of lemon juice and water in the bottle
0.6 x + 1 = x
Part B :
x - 0.6 x = 1
0.4 x = 1
x = 1 : 0.4
x = 2.5 lit.
Lemon juice: 2.5 * 0.6 = 1.5 lit.
6 0
3 years ago
A fish tank contains tetras,guppies,and minnows. The ratio of tetras of guppies.Is 4:2.The ratio is minnows of guppies is 1:3. T
oksano4ka [1.4K]

Answer:

30

Step-by-step explanation:

Let number of tetras be "t"

number of guppies be "g"

number of minnows be "m"

Ratio of tetras to guppies is 4:2, or reducing, 2:1. Thus we can write:

\frac{t}{g}=\frac{2}{1}\\t=2g

Ratio of minnows to guppies is 1:3, so we can write:

\frac{m}{g}=\frac{1}{3}\\g=3m

or, m = g/3

Also, total there are 60 fish, so we can write:

t + g + m = 60

or

2g + g + g/3 = 60

Solving this, we can solve for g. Shown below:

2g+g+\frac{g}{3}=60\\3g+\frac{g}{3}=60\\\frac{9g+g}{3}=60\\10g=180\\g=18

Now, finding t and m:

m = g/3 = 18/3 = 6

m = 6

and

t = 2g

t = 2(18)

t= 36

There are 36 tetras and 6 minnows. So, there are

36 - 6 = 30 more tetras than minnows

4 0
3 years ago
Answer this and you will get a bf or gf this yr
Olenka [21]
Haha very funny !!!!!!!!!!!!!
4 0
3 years ago
Read 2 more answers
Beginning with the equation x= -90, write the new equation produced by dividing both sides by 10
kobusy [5.1K]

Answer:

x/10 = -9

Step-by-step explanation:

You are given the equation: x = -90

You are asked to divide 10 from both sides. Simplify:

(x)/10 = (-90)/10

x/10 = -90/10

x/10 = -9

x/10 = -9 is your answer.

~

4 0
3 years ago
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