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statuscvo [17]
3 years ago
5

Can you helpthank you​

Mathematics
2 answers:
Lemur [1.5K]3 years ago
4 0

Answer:

In first box: top left __7, in top right __4, on left top __9, left bottom __6.

In second box: top left __7, in top right __3, on left top __3, left bottom __5.

Step-by-step explanation:

amm18123 years ago
4 0

Answer:

Here you go! I believe this is correct.

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I need help. Plz! ???
Troyanec [42]

Answer: No

Step-by-step explanation: No, because a proportional relationship is  a line that goes up at a constant rate, and goes through the origin, an example of a proportional relationship is a straight line starting from the origin ( or what we call the starting point)

3 0
2 years ago
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Lateral erea of cube​
jekas [21]

Answer:

4a2

Step-by-step explanation:

For a cube the lateral surface area would be the area of the four sides. If the edge of the cube has length a, the area of one square face Aface = a ⋅ a = a2. Thus the lateral surface of a cube will be the area of four faces: 4a2.

4 0
2 years ago
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What is the vertex of the graph of y = 1/3 (x-9)2 + 5 Question 1 options: (9,5) (3,3) (3,5) (-9,5)
svlad2 [7]
ANSWER

The vertex of the graph of
y =  \frac{1}{3}  {(x - 9)}^{2}  + 5
is

(9,5)



EXPLANATION

The vertex form of a parabola is given by

y = a {(x - h)}^{2}  + k

where
V(h,k)
is the vertex of the parabola.


The function given to us is

y =  \frac{1}{3}  {(x - 9)}^{2}  + 5
This is already in the vertex form.


When we compare this to the general vertex form, we have,

a =  \frac{1}{3}

h = 9
and

k = 5


Therefore the vertex of the parabola is

V(9,5)

Hence the correct answer is option A.

7 0
3 years ago
Read 2 more answers
Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.
dusya [7]

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

5 0
2 years ago
Read 2 more answers
Please Do 3 for 5 points.
alukav5142 [94]

Answer:

44, 46, and 48

Step-by-step explanation:

add them and you should get 138.

7 0
3 years ago
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