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slega [8]
3 years ago
7

I need help...... Write the domain and range of each of the functions graphed below. 1. Domain: ___________________ Range: _____

______________ 2. Domain: ___________________ Range: ___________________ 3. Domain: ___________________ Range: ___________________ 4. Domain: ___________________ Range: ___________________

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0

Answer:

Step-by-step explanation:

Domain of any function is represented by the x-values and Range is represented by the y-values.

Graph (1),(Row (1) first graph)

Domain → (-∞, ∞) Or set of all real numbers

Range → (-∞, ∞) Or set of all real numbers

Graph (2) (Row (1) second graph)

Domain → [0, ∞} Or x ≥ 0

Range → [-2, ∞) Or x ≥ -2

Graph (3) [Row (2) first graph]

Domain → (-∞, ∞) Or set of all real numbers

Range → (-∞, ∞) Or set of all real numbers

Graph (4) [Row (2) second graph]

Domain → (-∞, ∞) Or set of all real numbers

Range → [4, ∞) Or x ≥ 4

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Point A is at -7, -3. There are 12 points between A and B. What are possible coordinates for point B?
Finger [1]

Answer:

(5,9)

(-19, - 15)

(5, - 15)

(-19, 9)

Step-by-step explanation:

Given that :

Coordinate of point A = - 7, - 3

Number of points between point A and B = 12

Possible coordinate of point B

Possible coordinates of point B:

(-7, - 3) + 12 = (5, 9)

(-7, - 3) - 12 = (-19, - 15)

(-7, - 3) = (-7 +12, -3 - 12) = (5, - 15)

(-7, - 3) = (-7 - 12, - 3 + 12) = (-19, 9)

Hence possible coordinates of be are :

(5,9)

(-19, - 15)

(5, - 15)

(-19, 9)

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3 years ago
Which function has only one x-intercept at (-6, 0)?
Lelu [443]

Answer:

<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>

Step-by-step explanation:

The intercept form of a quadratic equation (parabola):

y=a(x-p)(x-q)

p, q - x-intercepts

Therefore

The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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