Someone please help me answer these questions?

2 answers:

8 0

When you are solving equations like this, you simply need to remember to combine like terms and isolate the variable to one side or the other.

1. 2x-17=4 (Add 17 to both sides....the left cancels out the -17)
2x= 21 (divide both sides by 2)
x = 10.5

2. (10x+5) + (6x-1) = 180 (combine like terms....the parentheses are there to just group them into different terms)
16x+4 = 180 (subtract 4 from both sides)
16x = 176 (divide each side by 16)
x = 11

3. 3x + 4 = 2x - 1 (isolate the variable to one side, let's go with the left and subtract 2x from both sides)
x + 4 = -1 (subtract 4 from both sides)
x = -5

4. 2(x + 4) = x + 13 (apply the distributive property to the parentheses)
2x + 8 = x + 13 (isolate the variable to the left side and subtract x)
x + 8 = 13 (subtract 8 from both sides)
x = 5

5. 14x = 2(5x + 14) (apply distributive property to the right side)
 14x = 10x + 28 (isolate the variable to the left, subtract 10x)
4x = 28 (divide both sides by 4)
x = 7

Hope all the steps are clear and you can see why each step was taken. Good luck!

lapo4ka [179]3 years ago

6 0

1. 21/2 or 10.5
2. 11
3. -5
4. 5
5. 7
I hope this answers all of your problems! Good luck with the rest of your homework!

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First step is to simplify the inside of the radical. There are x's on both top and bottom of the fraction. So we subtract their exponents. x³ - x¹ = x². Because the x³ was in the denominator and it was bigger, the x² goes on the bottom.

Your new equation is:

$\sqrt{\frac{126y^{5}}{32x^{2}} }$

Now, I'd suggest factoring each term to correspond with the square root.

126y⁵ = 9 · 14 · y² · y² · y

32x² = 4 · 4 · 2 · x²

9, y², and y² can be square rooted in the numerator. 4, 4, and x² in the denominator. So we pull out their square roots and place them outside of the radical. The rest stays in the radical:

$\frac{3 * y * y}{2*2*x}\sqrt{\frac{14y}{2}}$