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julia-pushkina [17]
3 years ago
15

Someone please help me answer these questions?

Mathematics
2 answers:
svp [43]3 years ago
8 0
When you are solving equations like this, you simply need to remember to combine like terms and isolate the variable to one side or the other.  

1.  2x-17=4 (Add 17 to both sides....the left cancels out the -17)
     2x= 21   (divide both sides by 2)
     x = 10.5  

2.  (10x+5) + (6x-1) = 180  (combine like terms....the parentheses are there to just group them into different terms)
     16x+4 = 180  (subtract 4 from both sides)
     16x = 176  (divide each side by 16)
      x = 11

3.  3x + 4 = 2x - 1 (isolate the variable to one side, let's go with the left and subtract 2x from both sides)
     x + 4 = -1  (subtract 4 from both sides)
      x = -5

4. <span> 2(x + 4) = x + 13  (apply the distributive property to the parentheses)
   2x + 8 = x + 13  (isolate the variable to the left side and subtract x)
   x + 8 = 13  (subtract 8 from both sides)
   x = 5

</span><span>5.  14x = 2(5x + 14)  (apply distributive property to the right side)
</span>    14x = 10x + 28  (isolate the variable to the left, subtract 10x)
    4x = 28  (divide both sides by 4)
     x = 7

Hope all the steps are clear and you can see why each step was taken.  Good luck!
lapo4ka [179]3 years ago
6 0
1. 21/2 or 10.5
2. 11
3. -5
4. 5
5. 7
I hope this answers all of your problems! Good luck with the rest of your homework!
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Answer:

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Step-by-step explanation:

The value of the velocity v is given as:

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When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

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4 years ago
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3 years ago
The coordinates of the vertices of ∆PQR are P(-2,5), Q(-1,1), and R(7,3). Determine whether ∆PQR is a right triangle. Show your
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<span>Triangle PQR is a right triangle. First we have to find the length of each side of the triangle. This can be done using the points provided, along with the Pythagorean theorem, which is a^2+b^2=c^2. PR^2 = (7- -2)^2+(3-5)^2 = 85 => PR = sqrt(85) QR^2 = (7- -1)^2+(3-1)^2 = 68 => QR = sqrt(68) QP^2 = (1-5)^2+(-1 - -2)^2 =17 => QP = sqrt(17) Now that we have the sides of the triangle, we can put them into the Pythagorean theorem again to see that it works out: (Sqrt(17))^2 + (sqrt(68))^2 = (sqrt(85))^2 17 + 68 = 85 85 = 85 Since the Pythagorean theorem works for right triangles, the triangle is indeed a right triangle.</span>
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4 years ago
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pickupchik [31]
Answer:
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Explanation:
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3 years ago
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List ALL possible rational zeros for the following function:<br> f(x)=3x^3-20x^2+33x-14
Wewaii [24]

Answer:

Possible rational roots: ±1, ±1/3, ±2, ±2/3, ±7, ±7/3, ±14, ±14/3A.

Actual rational root: 2/3A.

Step-by-step explanation:

Hope this helps!

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