3 years ago

4x + 7y = 3 x = y - 2

Mathematics

2 answers:

liberstina [14]3 years ago

8 0

First equate 4x+7y=3x,

we get, x+7y=0 ---->equ 1

Now equate 3x=y-2, we get 3x-y=-2 ----->equ2

solve equ 1,2,

We get x= -7/11, y=1/11

DiKsa [7]3 years ago

4 0

Plus x i

4(y-2) + 7y =3

4y-8+7y=3

11y-8=3

11y=3+8

11y=11

Y = 1

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6 0

3 years ago

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bazaltina [42]

Step-by-step explanation:

x= 20

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7 0

4 years ago

F(2) = 20 and f(3) = 12

Illusion [34]

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8 0

4 years ago

Select all the common denominators for 8/3 and 5/6 .......12, 24, 32, 36, 48

BabaBlast [244]

Hello.

The answer to your question is =
12, 3 x 4 and 6 x 2.
24, 3 x 8 and 6 x 4.
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So it's pretty much everything except for 32.
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6 0

4 years ago

Read 2 more answers

Consider xưy" – 14xy' + 56y = 0. Find all values of r such that y=x" satisfies the differential equation for x > 0. Enter as

beks73 [17]

I bet the ODE is supposed to read

$x^2y''-14xy'+56y=0$

Then if $y=x^r$ , we have $y'=rx^{r-1}$ and $y''=r(r-1)x^{r-2}$ , and substituting these into the ODE gives

$r(r-1)x^r-14rx^r+56x^r=0\implies r(r-1)-14r+56=r^2-15r+56=0$

Solving for <em>r</em>, we find

$r^2-15r+56=(r-8)(r-7)=0\implies \boxed{r=8\text{ or }r=7}$

so that $y_1=x^8$ and $y_2=x^7$ are two fundamental solutions to the ODE. Thus the general solution is

$\boxed{y(x)=C_1x^8+C_2x^7}$

Given that $y(1)=4$ and $y'(1)=3$ , we get

$\begin{cases}4=C_1+C_2\\3=8C_1+7C_2\end{cases}\implies C_1=-25\text{ and }C_2=29$

So the particular solution is

$\boxed{y(x)=29x^7-25x^8}$

4 0

4 years ago