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3 years ago

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1) Complete the following items dealing with sets.

1 answer:

Ivanshal [37]3 years ago

3 0

From the set {21, 37, 45}, use substitution to determine which value of x makes the inequality true.x - 8 > 29
45
none of these
37
21From the set {21, 37, 45}, use substitution to determine which value of x makes the inequality true.x - 8 > 29
45
none of these
37
21

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If a bus traveled 400 miles in 8 hours, what was the average speed of the bus in miles per hour

MaRussiya [10]

Answer:

50 Miles per hour

Step-by-step explanation:

To find the average speed divide the distance by the time it took to cover that distance

400/8=50

So the bus traveled 50 miles per hour on average.

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3 years ago

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The linear equation 99(xminus−77)equals=99(xplus 88) is

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99(x-77)=99(x+88)
99x-7623=99x+8712
99x-99x=8712+7623
0=670824.no solution as x becomes 0

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3 years ago

The following table shows the expressions that represent the sales of 4 companies:

weeeeeb [17]

I think it might be (B), not for sure but it has to be (B)

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4 years ago

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The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately <u>63.7 ft.</u>

The braking distance at 55 mph, is approximately <u>298.35 ft.</u>

The braking distance at 85 mph, is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

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2 years ago

20 + 27x + 9x^2 = (?) (3x + 5)

DiKsa [7]

Answer:

(3x + 4)

Step-by-step explanation:

9x²+27x+20 can be factored out to (3x + 4)(3x + 5)

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3 years ago