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jeyben [28]
3 years ago
12

In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz

at all, and decides to randomly guess the answers. Find the probabilities of each of the following events: (a) the first question she gets right is the 3rd question
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer:

We have 20 category Questions split into 5

Where we would assume that the 3rd question is simply 1/4 + 5/20 chance.

This is not a determiner as Robin is asked more questions.

So it is simply 1/4 and kept to factors that Robin will answer one of the 4 choices upon the 3rd question as 1/4 regardless of other questions being asked. Where Robins first answer would be the third question we subtract 4/5 = 16/20 - 5/20= 11/40. Which can only be rounded down to 2 decimal places 0.275

Step-by-step explanation:

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Read 2 more answers
Lizzie came up with a divisibility test for a certain number $m \neq 1$:
fiasKO [112]

Answer:

Lizzie came up with a divisibility test for a certain number $m \neq 1$:

Break a positive integer n into two-digit chunks, starting from the ones place. (For example, the number 354764 would break into the two-digit chunks 64, 47, 35.

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Step-by-step explanation:

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