Look at the sample space below. {1, 2, 3, 7, 9, 10, 15, 19, 20, 21} When chosen randomly, what is the probability of picking an
maw [93]
Answer:
the probability of picking an odd number is 7/10
Answer:
C. 5x + 11 = 36
Step-by-step explanation:
You can see in the diagram that there are 5 x variables and eleven which make up the total diagram that says 36 so it would have to be 5x+11 = 36
Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
Go 0.35•22 and you get 7.7
