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IceJOKER [234]
3 years ago
5

Please please help with these two !!! i’ll give brainliest pls

Mathematics
1 answer:
arsen [322]3 years ago
3 0

Answer:

1.)B

2.)C

I apologize if this answer is wrong.

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If tñ=2ñ+3, find S10​
Allisa [31]

Answer:

S_{10}=280

Step-by-step explanation:

Given that,

t_n=2n+3 ...(1)

We need to find the value of S_{10}.

Put n = 1 to find the first term.

t_1=2(1)+3=5

Put n = 2 to find the second term.

t_2=2(2)+3=7

Put n = 3 to find the third term.

t_3=2(3)+3=9

Put n = 10 to find the tenth term.

t_{10}=2(10)+3=23

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

S_=\dfrac{n}{2}(a+a_n)

We have, n = 10, a = 5 and a_n=23

So,

S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280

So, the value of S_{10} is equal to 280.

3 0
3 years ago
Write a formula for g(x) in terms of x.
liberstina [14]

The formula of g(x) is g(x) = -0.8x - 1.6

<h3>How to determine the formula of g(x)?</h3>

The equation is given as:

-4x - 6 = 5y + 2

Subtract 2 from both sides

5y = -4x - 8

Divide through by 5

y = -0.8x - 1.6

Express as a function

g(x) = -0.8x - 1.6

Hence, the formula of g(x) is g(x) = -0.8x - 1.6

Read more about linear functions at:

brainly.com/question/4025726

#SPJ1

3 0
1 year ago
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
Which expression best estimates Negative 18 and one-fourth divided by 2 and two-thirds?
Mars2501 [29]

Answer:

-18/3

Step-by-step explanation:

5 0
3 years ago
I don’t understand what the answer is
lina2011 [118]

Answer:

3.14

Step-by-step explanation:

7 0
3 years ago
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