Answer:
1/36
Step-by-step explanation:
On the first throw, the probability of rolling any particular number, 1 through 6, is 1 out of 6. So the chance of rolling a 4 is 1/6.
On the second roll, your probability of rolling a 2 is 1/6.
The 'trick' is knwoing what to do with those two numbers.
Here's the rule: If events are dependent on one another, you multiply the probabilities.
Any time you see a scenario where X has to happen <u>and then </u>some other thing (X, Y, or whatever) has to happen, the events are dependent.
Probability of rolling a 4 <u>and then</u> rolling a 2 = 1/6 * 1/6 = 1/36
Hope this helps.
Thxxxxxxxxxxxxxx. Xxxxxxxxx
You solve this by plugging one equation into the other. Usually you have to rewrite one equation to make this work. In this case I choose to rewrite y-4x=0 as y=4x.
After plugging it into the second, you get:
3x + 6*4x = 9 => 27x = 9 => x=1/3
Putting this solution back into y=4x gives us y=4/3
