All categories

3 years ago

Combining like terms -4x-10x

Mathematics

1 answer:

vlabodo [156]3 years ago

6 0

Answer:

-4x -10x

See both terms contain a common multiple x

and HCF of 4 and 10 is 2

So, take -2x common

-2x( 2 +5)

= -2x(7)

=-14x

You might be interested in

Which pair of variables can’t be represented on a scatter plot?

nalin [4]

Answer:dotted variables cannot

Step-by-step explanation:

its right trust me

8 0

3 years ago

A grocery store sells 6 ears of corn for $3.54. Which of the fllowing shows how to find the amount of money that each ear of cor

Vlad [161]

Answer: B: 6÷3.54

Step-by-step explanation: Since they sold 6 ears and made $3.54 total, you would have to divide 6 by $3.54 to determine the cost of each ear.

4 0

3 years ago

Please help 20 points

zysi [14]

Answer:

i think 65 but if not then it is D impossible

Step-by-step explanation:

hope that helps

and that i wasn't to late

6 0

3 years ago

Which of the following is NOT a characteristic of a plane?

sveta [45]

Answer:

A). thickness are correct

3 0

3 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship $\sin{\theta} < \cos{\theta}$ holds for all acute angles? (That is, $0^{\circ} < \theta$ ?) It turns out that:

$\sin{\theta} < \cos{\theta}$ if $0^{\circ} < \theta$ ;
$\sin{\theta} > \cos{\theta}$ if $45^{\circ} < \theta$ ;
$\sin{\theta} = \cos{\theta}$ if $\theta = 45^{\circ}$ .

4 0

3 years ago

Read 2 more answers