Answer:
31.4
Step-by-step explanation:
Each side of the square has a length of 40 × = 10 inches. 4
The perimeter of the square minus the circumference of the circle is 40 − 31.4 = 8.6
The radius of the circle is 10 = 5 inches, so the circumference of the circle is 2
2 × π × 5 = 10 × 3.14 = 31.4 inches.
Round to the what? Tenths? Hundredths? Thousandths?
Tenths: 270735. 8
Hundredths: 270736.84
Thousandths: 270735.836
The answer would be 21 I believe
To find the z-score for a weight of 196 oz., use
![z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3D%5Cfrac%7B196-180%7D%7B8%7D%3D%5Cfrac%7B16%7D%7B8%7D%3D2)
A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.