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Sergio039 [100]
3 years ago
8

Which if any of the blood samples can the patient with type b+ blood receive

Biology
1 answer:
KIM [24]3 years ago
6 0

I think it is A + blood

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When Penguin Catering Services first opened, the owner decided to target only events at resorts in its geographic region. Pengui
rusak2 [61]

Answer:

The answer is concentrated

Explanation:

Concentrated targeting strategy may also called niches targeting. This is a situation whereby an organization /firm directs all its energy or efforts on a single market part.

Penguin Catering Services used concentrated targeting marketing because it focus/limit its  target to only event at resorts in its geographical region.

4 0
3 years ago
Compare the amount of ATP made during aerobic cellular respiration to the amount of ATP made during anaerobic cellular respirati
andreyandreev [35.5K]

The answer is C. Because aerobic cellular respiration includes oxygen in the process, more ATP (specifically 36-38 ATP) is produced. Because anaerobic cellular respiration does not include oxygen in the process, it only produces 2 ATP.

6 0
3 years ago
Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004
Simora [160]

Hardy Weinberg Equilibrium

Explanation:

  • Hardy Weinberg Equilibrium formula for allelic frequency is: p+q=1
  • Hardy Weinberg Equilibrium formula for genotypic frequency is: p^2+q^2+2pq=1
  • Here,p=frequency of dominant allele

                 q=frequency of recessive allele

                 p^2=frequency of dominant genotype

                 q^2=frequency of recessive genotype

                 2pq=frequency of heterozygous genotype

  • frequency of affected individuals=0.0004(given)

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as:     q^2=0.0004

  • If q^2=0.0004 q will be 0.02;frequency of recessive allele will be 0.02
  • Using the formula p+q=1

                                       p+0.02=1\\p=1-0.02=0.98

  • hence,frequency of dominant allele will be 0.98
  • Frequency of dominant genotype will be p^2=(0.98)^2=0.9604
  • Frequency of heterozygous genotype will be 2pq=2*0.98*0.02=0.0392

7 0
3 years ago
Throughout human history, people have always consumed the milk of other animals
Phoenix [80]
What's the questions that's a statement


5 0
3 years ago
Read 2 more answers
rabbits can have curly ears or long ears. a homozygous curly-eared rabbit mated with a homozygous long-eared rabbit. all the bab
charle [14.2K]
Long ears have to be dominant:

If this IS true then these would be your 'parents':

L = long ears
l = curly ears

LL x ll

If you cross the homozygous recessive curly eared rabbit (ll) with homozygous dominant long eared rabbit (LL) you would get 100% Ll - all would look long eared.
3 0
3 years ago
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