Both provide approach to confirming the result of experimentation.
The answer is false. To explain further, let G have vertices
{v1, v2, v3, v4}, with ends between each pair of vertices, and with the mass on
the edge from vi to vj equal to I + j. Then each tree has a bottle neck edge mass
of as a minimum of 5, so the tree containing of a track through vertices v3, v2,
v1,v4 is a least bottleneck tree. It is not a least spanning tree, though, subsequently
its total mass is greater than that of the tree with edges from v1 to every
single vertex.
<span>Python is Highly case sensitive language. We can use > , < , <= , <= , == , != to compare two strings. Python compares string using ASCII value of the characters.
For example name as "MIDHUN" and name1 as "Midhun" . The first two characters from name and name1 ( M and M ) are compared. As they are equal, the second two characters are compared. Since the ASCII values are not equal the result is not equal.</span>
The correct answer would be Polyploide.
Hope that helped!
-astroworld301