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nadezda [96]
3 years ago
13

288,500 house with a 30 yr mortgage and 3.25% interest rate is

Mathematics
1 answer:
Murljashka [212]3 years ago
5 0

A good deal on the mortgage I suppose. A bit expensive, but if you have the money go for it.

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Can you please help me?!
Fudgin [204]

Answer:

A and B are correct

Step-by-step explanation:

4 0
3 years ago
Quadratic equations are never used to solve word problems. True or false?
mel-nik [20]
Quadratic equations CAN be used to solve word problems so the answer to your question is false
7 0
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You work 40 hours/week for 50 weeks and are given the option to be paid hourly or to go on salary. In which situation will you e
Alenkasestr [34]

Answer:

40/50 weeks is the ans

plzzz give brainliest

5 0
3 years ago
Using elimination to solve the system 2x + y = 8 and x + y = 4, which of the following could be the first step?
wolverine [178]
Answer: the option A.

The elimination method consist is adding the two equations in a way that one variable be eliminated..

In order to do that you might have to manipulate on of the equations prior to add the two equations.

In this case, ff you multiply the second equation by - 1 you will get

  - x - y = - 4

which you can add to the first equation

   2x + y = 8 to eliminate the y.

 
4 0
3 years ago
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
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