Answer:
Option 1 and 3 are correct which indicate that fifty percent of the data values lie between 34 and 46, and it is unlikely there are any outliers.
Step-by-step explanation:
As the plot is not given, by an online search, same question is found online for which the plot is given as attached herewith.
From the box plot:
median=46
Q1=42
Q3=70
Q3-Q1= IQR=70-42=28
max=76
min=34
Range=max-min=76-34=42
no outliers seen from boxplot
only (1)and (3)are correct.
Given that D is the mid point of CE ,
So D will bisect CE, it means the length of DE and CD is equal.
=> DE + CD = CE
As DE and CD are equal,
=> DE + DE = CE
=> 2 DE = CE
Putting values from the question,
=> 2( 7x - 1 ) = 10x + 18
=> 14x - 2 = 10x + 18
=> 14x - 10x = 18 + 2
=> 4x = 20
=> x = 20 / 4
=> x = 10 / 2
=> x = 5
Therefore, the value of x is 5
So, looking at how many seniors there are, you can see that there are 35 of them. 25 are in sports, 5 are in music/drama, and 5 work. If you added them altogether, you get 35. Now, the chance of them being in sports is 25/35 chance/probability. You can simplify 25/35 because both of them are divisible by 5. 5 times 5= 25 and 7 times 5=35. Therefore, the answer is 5/7.
Answer:
(3, - 1)
Step-by-step explanation:
5x - 4y = -11
2x + 3y = -9
Multiply the top equation by 2 and the bottom equation by - 5 to cancel out the x's.
10x - 8y = - 22
- 10x - 15y = 45
Cancel out x's.
-8y = - 22
- 15y = 45
Add like terms.
- 23y = 23
Can't have a negative variable to flip them.
-23 = 23y
Divide.
y = - 1
Input y into one of the equations and solve for x.
2x + 3(-1) = -9
Simplify.
2x -3 = -9
Cancel out -3 by adding 3.
2x = -6
Divide.
x - -3
3a-2 is equivalent to (3a)-2
Hope my answer helped:)
