The original price for one lunch special is $19.
<em><u>Explanation</u></em>
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay
dollar each day</u>.
So, the total amount needed to pay for 5 days
dollar
Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....

So, the original price for one lunch special is $19.
Hey, I’m pretty sure the answer is y=1/2x + 0.
To explain, we can plug the x value into the equation for all of the x values, and we will get our y value.
So the first one,
y=1/2(1) + 0 —> 1/2
The second one,
y=1/2(2) + 0 —> 1
And so forth, the rest of the equations will be correct. I hope that helps ! :D
Answer:
sin(4π/21)
Step-by-step explanation:
Step 1: Rearrange expression
sin(π/3)cos(π/7) - cos(π/3)sin(π/7)
Step 2: Use sin(A ± B)
sin(π/3 - π/7)
Step 3: Evaluate
sin(4π/21)
And we have our answer!
8 - 8x is already in its simplest form.
Without knowing the value of x, you cannot find what is equivalent to 8 - 8x, but you can it if is an equation, such as 8 - 8x = 88 (x would be -10).
However, you can still rewrite it as -8x + 8, which is equivalent to 8 - 8x.
Answer:
A two-sample t-test for a difference between sample means
Step-by-step explanation:
<u>Explanation</u>:-
A random sample of 50 bags from each of Brand X and Brand Y was selected
Given two sample sizes n₁ and n₂
Each bag was held from its rim, and one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped
mean of ounces the first sample = x⁻
mean of the second sample =y⁻
Given data one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped
Standard deviation of the first sample = S₁
Standard deviation of the second sample = S₂
Now we use t - distribution for a difference between the means

where

Degrees of freedom γ = n₁ +n₂ -2