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3 years ago

HELP ME PLEASE ASAP IT'S AN EMERGENCY

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

The answer is b.

This is because the line is sloping downwards, and so y = -1

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The circumference of a circle is 53.3853.38 centimeters.

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Step-by-step explanation:

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3 years ago

How how is 1/2 + 1/4 solve differently than 1/2 + 1/3?

yulyashka [42]

1/2 + 1/4 =
2/4 + 1/4 =
3/4 <===

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3 years ago

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Can someone please help me with these math problems please!

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Answer:

Step-by-step explanation:

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3 years ago

[MATH] I need help on all of them! Please and thank you <33

REY [17]

Answer:

2) 45

3) 25

4) 50%

5) 33.3%

6) 17.6

7) 500

8) 35%

9) 60

10) 87.5%

11) 2.64

12) 25%

13) 5.7

14) 85%

16) 75%

Step-by-step explanation:

2) 9 = 20% of x

9 * 5 = 45

3) 8% of x = 2

12.5 * 2 = 25

4) 39 = x(78)

39/78 = 1/2 = 50%

5) x(36) = 12

12/36 = 1/3 = 33.3...%

6) x = 0.8(22)

22/10 = 2.2

2.2* 8 = 16 + 1.6 = 17.6

7) 55 = 0.11(x)

55/11 = 5

5 * 100 = 500

8) 7/20 = 35/100 = 35%

9) 27 = 0.45(x)

27/45 = 3/5

3/5 * 100 = 300/5 = 60

10) . 49/56 = 7/8 = 0.875 = 87.5%

11) 6/100 = 0.06

0.06 * 44 = 2.64

12) 48/192 = 6/24 = 1/4 = 25%

13) 95/100 = 0.95

0.95 * 6 = 5.40 + 0.3 = 5.7

14) 68/80 = 34/40 = 17/20 = 85%

16) 108/144 = 9/12 = 0.75 = 75%

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-Chetan K

3 0

3 years ago

2. When a large truckload of mangoes arrives at a packing plant, a random sample of 150 is selected and examined for

kirza4 [7]

a) The 90% confidence interval of the percentage of all mangoes on the truck that fail to meet the standards is: (7.55%, 12.45%).

b) The margin of error is: 2.45%.

c) The 90% confidence is the level of confidence that the true population percentage is in the interval.

d) The needed sample size is: 271.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

The variables are listed as follows:

$\pi$ is the sample proportion, which is also the estimate of the parameter.

z is the critical value.

n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of $\frac{1+0.90}{2} = 0.95$ , so the critical value is z = 1.645.

The sample size and the estimate are given as follows:

$n = 150, \pi = \frac{15}{150} = 0.1$

The margin of error is of:

$M = z\sqrt{\frac{0.1(0.9)}{150}} = 0.0245 = 2.45\%$

The interval is given by the estimate plus/minus the margin of error, hence:

The lower bound is: 10 - 2.45 = 7.55%.

The upper bound is: 10 + 2.45 = 12.45%.

For a margin of error of 3% = 0.03, the needed sample size is obtained as follows:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.1(0.9)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.1(0.9)}$

$\sqrt{n} = \frac{1.645\sqrt{0.1(0.9)}}{0.03}$

$(\sqrt{n}})^2 = \left(\frac{1.645\sqrt{0.1(0.9)}}{0.03}\right)^2$

n = 271 (rounded up).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

3 0

1 year ago