Answer:
F. Picture F
Step-by-step explanation:
Answer:
0.00007935
Step-by-step explanation:
7.935 x 10 to negative 5 power can be written as:
7.935 x 10^(-5)
A trick to finding 10 to the x power, x is the number of 0's. So 10^5 = 100000

When dividing by tens, move the decimal to the left by the amount of 0's
So our answer is 0.00007935
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
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Answer: 
Step-by-step explanation:
Sine uses the ratio,
so we can plug in the information we know. since there is no current value for the opposite side of angle A, we can just use a variable to replace it.

You can't reduce this any further because there is an unknown variable.