Answer: 162 plants
Step-by-step explanation: 270 times 3/5= 162 plants
So i’m not sure about this but you would do the y=mx+b form and then since slope = m it would be y=-5x+b and then you would plug 7 and -3 for y and x and then you would get 7=-5-3=b and then solve for b
Answer:
P(n)= p0 + 11(n)
Where p0= population of week 0
P(n) = population of n weeks
n= number of weeks
Step-by-step explanation:
Population of beetles in Week 0= 6
Population of beetles in Week 7= 83
From week 0 to week 7 there are 8 weeks.
But subtracting population of week 0 from population of week 7 gives
= 83-6
= 77
After the subtraction, we have 7 weeks remaining.
Dividing the remaining population by the number of weeks remaining
=77/7
= 11
For n number of weeks, population p of beetles
P(n)= p0 + 11(n)
Where p0= population of week 0
P(n) = population of n weeks
n= number of weeks
Answer: 1/1000
Step-by-step explanation:
1 * 10^-3 = 1 * 1/10^3 = 1/1000
Answer:
z (min ) = 0.4167 $
x = 8,33 oz
y = 0
Step-by-step explanation:
Table:
Vitamin A Vitamin B Cost $/oz
Wheat (x) 10.5 2.4 0.05
Oats (y) 6 1.8 0.10
Requirements 48 (mg) 20 (mg)
Requirements 1,693 (oz) 0,7054 (oz)
The problem is minimized z subject to two constraint
z = 0.05*x + 0.1*y to minimize
Subject to:
Requirement of Vitamin A
10.5*x + 6 * y ≥ 48
Requirement of Vitamin B
2.4*x + 1.8*y ≥ 20
x≥0 y≥0
Using the on-line solver AtomZmaths and after 3 iterations the solution is:
z (min ) = 0.4167 $
x = 8,33 oz
y = 0
