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sesenic [268]
3 years ago
10

What is the product of any integer and –1?

Mathematics
1 answer:
morpeh [17]3 years ago
7 0
Since negative 1 is negative, we multiply by 1 and make it negative. Therefore, if the integer is x, the product of that and negative 1 is -1*x=-x
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Add using a number line.<br> +(-11)
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As it is present in left side, so -11 will be in left part of number line.

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Help me with this plzzz
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2/3

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Brett and Greg each want to run for president of their school’s student body Council. in order to do so, they must collect a cer
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3 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
If 3 is subtracted from twice a number, the result is 8 less than the number. Write an equation to solve this problem.
lakkis [162]
3 subtracted from twice a number=2x-3
8 less than the number=x-8
2x-3=x-8
x=-5
3 0
3 years ago
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