Answer:
if the area of the rectangle is the same then the height of the triangle would be double that of the rectangle
Step-by-step explanation:
this is because the formula for working out the area of a triangle is base multiplied by height divided by 2 and so will need to be double to overcome the dividing factor.
Answer:
The zero of the equation represents the maximum height attained by the shot put.
Step-by-step explanation:
William is competing in the shot put event at a track meet. The quadratic expression that models the vertical height of the shot from the ground is
H = 
We can find the zeroes of these two equations.
For that put H = 0.
= 0
(-2x + 5)(x + 1) = 0
x= -1 or x = 2.5
x= -1 is neglected as it is not practical.
x = 2.5 is the maximum height attained by the shot put.
The zero of the equation represents the maximum height attained by the shot put.
Answer:
Option B: a continuous random variable.
Step-by-step explanation:
The weight of a body can be defined as the force with which the earth pulls that object towards itself.
Mathematically,
W = mg
As weight is the force with unit NEWTON so it is a continuous variable which can attain any value in decimal.
Answer: 40 ft^3
Step-by-step explanation:
l*w*h to find volume of space in the drawer so
5*4=20 and 20*2= 40 so the volume is 40
Answer:
see below
Step-by-step explanation:
The sequence of letters in a congruence statement is important: it tells you the corresponding parts.
A triangle, such as ΔCAT, is named using the names of its vertex points. When it is said to be congruent to ΔDOG, it means these correspondences (and congruences) exist:
- angle C to angle D . . . . . first letters correspond
- angle A to angle O . . . . . second letters correspond
- angle T to angle G . . . . . third letters correspond
- segment CA to segment DO . . . . . named by 1st & 2nd letters
- segment AT to segment OG . . . . . named by 2nd & 3rd letters
- segment CT to segment DG . . . . . named by 1st & 3rd letters
Only one of these is on your list of answer choices:
m∠A = m∠O