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Anton [14]
3 years ago
6

PLEASE HELP 8th GRADE MATH QUESTION OVER HERE!!!

Mathematics
1 answer:
patriot [66]3 years ago
6 0

The side AB measures option 2. \sqrt{20}} units long.

Step-by-step explanation:

Step 1:

The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).

The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.

To calculate the distance between two points, we use the formula d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}.

where (x_{1},y_{1}) are the coordinates of the first point and (x_{2},y_{2}) are the coordinates of the second point.

Step 2:

For A (4, 5) and B (2, 1), (x_{1},y_{1}) = (4, 5) and (x_{2},y_{2}) = (2, 1). Substituting these values in the distance formula, we get

d=\sqrt{\left(2-4\right)^{2}+\left(1-5}\right)^{2}} = \sqrt{\left(2\right)^{2}+\left(4}\right)^{2}}=\sqrt{20}}.

So the side AB measures \sqrt{20}} units long which is the second option.

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