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Bingel [31]
3 years ago
10

Someone help me with this question pleaseee

Mathematics
2 answers:
Alona [7]3 years ago
4 0

Answer:

y = 2x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = B(2,3) and (x₂, y₂ ) = A(4, 7)

m = \frac{7-3}{4-2} = \frac{4}{2} = 2, thus

y = 2x + c ← is the partial equation of the line

To find c substitute either of the 2 points into the partial equation

Using (2, 3), then

3 = 4 + c ⇒ c = 3 - 4 = - 1

y = 2x - 1 ← equation of line

sweet-ann [11.9K]3 years ago
3 0
Answer: y=2x-1

We know that the equation of a line is y = mx + b, where m is the gradient and b is the y-intercept.

First to find the gradient, we use the formula y2-y1/x2-x1.

x1 and y1 being the first set of coordinates (2,3) and x2 and y2 being the second set (4,7)

Now we sub in:
m=7-3/4-2
m=4/2
m=2

This is our gradient and we can put it into the equation: y=2x+b

Now we find the y-intercept (b). Since the y-intercept isn’t shown, we can sub in the coordinates to find it.

y=2x+b
Sub (2,3)
3=2(2)+b
3=4+b
-1=b

Sub (4,7)
7=2(4)+b
7=8+b
-1=b

Subbing in both coordinates gives us -1 as the y-intercept, so the finished equation is: y=2x-1
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Answer:

a

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   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

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c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

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Generally the sample proportion is mathematically represented as  

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=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

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=>   \alpha = 0.05

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   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

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