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ExtremeBDS [4]
3 years ago
8

In 2008, the price of gasoline was $2.79 per gallon. In 2009, the price of gasoline was

Mathematics
1 answer:
ikadub [295]3 years ago
7 0

Answer:

36%

Step-by-step explanation:

line up $ and % data like this:

$2.79 represents 100%

$3.79 represents  X%

cross multiply

X*2.79 = 3.79*100

divide both sides by 2.79

X= 3.79*100 / 2.79 ≈ 136%

so it increased 36%

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P(z < x) = 0.6064 - 0.5 = 0.1064

From the normal distribution table
P(z < 0.27) = 0.1064

Therefore the z-score is 0.27

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A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?
Butoxors [25]

The number of combinations will be 6 for even numbers.

<h3>What is the combination?</h3>

The arrangement of the different things or numbers in a number of ways is called the combination.

Given that:-

  • A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?

The total sample numbers are from 0 to 5 which are 0,1,2,3,4,5.

The even numbers are 0,2,4.

The combinations will be given by:-

C = 3!

C = 3 x 2 x1

C = 6

Therefore the number of combinations will be 6 for even numbers.

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3 0
2 years ago
State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes
Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let  quantity of  products A=x

Quantity  of products B=y

Product A takes time on machine L=2 hours

Product A takes time on machine M=2 hours

Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

Machine L can used total time= 8hours

Machine M can used total time= 6hours

Profit on product A= $9

Profit on product B=$7

According to question

Objective function Z=9x+7y

Constraints:

2x+3y\leq 6

2x+4y\leq 8

Where x\geq 0, y\geq 0

I equation 2x+3y\leq 6

I equation in inequality change into equality we get

2x+3y=6

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get 0\leq 6

Hence, this equation is true then shaded regoin is  below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get 2x+4y=8

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point  A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

0\leq 8

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= 9\times 0+7\times 2=14

At point O(0,0)

Z=0

At point B(3,0)

Z=9\times3+7\times0=27

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0
3 years ago
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gizmo_the_mogwai [7]

Answer:

2

Step-by-step explanation:

Drawing a table to show the different weather and mood options :

The degree of freedom :

________ WEATHER ________

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Here, we have a contingency table formatted in rows and columns

The columns = 3

The rows = 2

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(2 - 1) * (3 - 1)

1 * 2

= 2

The degree of freedom = 2

6 0
3 years ago
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