To solve the question we proceed as follows:
mean=142
standard deviation=14
a] Find the interval in which 68% of the data lies:
P(x<X)=68%=0.68
the z-score associated with this probability is:
P(z<Z)=0.47
but :
z=(x-mu)/sig
thus;
0.47=(x-142)/14
solving for x we get:
x=148.58
thus 68 percent of the data lie below 148.58
b]<span>what is the probability that a man picked at random from the unit will weigh more than 170 pounds?
</span>x=170
thus
P(x>170) will be:
z=(170-142)/14
z=2
Thus
P(x>170)=1-P(z<2)
=1-0.9772
=0.0228
c] <span>that he will weigh less than 128 pounds?
P(x<128)
z=(128-142)/14
z=(-14/14)=-1
Thus
P(z<-1)=0.1587</span>
Answer:
15x - 4
Step-by-step explanation:
Add both of the equations together.
f(x) + g(x)
(3x + 10x) + (2x -4)
Then, combine like terms
3x + 2x + 10x = 15x
15x - 4
Answer:
8.57x+1.06
Step-by-step explanation:
add: 5.47x+3.1x = 8.57
add: -8.84+9.9 = 1.06
The gcm is 30 and the lcm is 5