Well there are 7 boys and 10 students total so 7/10=0.7=70%. Therefore there is a 70% chance.
Answer:
give me a minute i will answer
Step-by-step explanation:
Answer:
a) 2.188
b) John's rent is not an outlier
c) His rent has to be higher than $1,235 to be an outlier
Step-by-step explanation:
The mean monthly rent of students at Oxnard University is $780 with a standard deviation of $208.
(a) John’s rent is $1,235. What is his standardized z-score?
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = $1235
μ is the population mean = $780
σ is the population standard deviation = $208
Hence,
z = 1235 - 780/208
z = 2.1875
Approximately to 3 decimal place = 2.188
(b) Is John’s rent an outlier?
No it isn't
(c) How high would the rent have to be to qualify as an outlier?
John’s rent would have to be higher than $1235
the awenser is 20 bla bla bla
Answer:
The 95% confidence interval for the population mean weight of newborn elephants is between 242.12 pounds and 245.88 pounds.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 244 - 1.88 = 242.12 pounds.
The upper end of the interval is the sample mean added to M. So it is 244 + 1.88 = 245.88 pounds
The 95% confidence interval for the population mean weight of newborn elephants is between 242.12 pounds and 245.88 pounds.
