All categories

3 years ago

14. Sarah swam 200 meters more than Molly.

Mathematics

2 answers:

mylen [45]3 years ago

8 0

Answer:you add 200 to 800 and you get 1100

Step-by-step explanation:

inn [45]3 years ago

4 0

Molly swam 600 metres. This is because you take away 200 metres and get how many metres molly swam

You might be interested in

How many minutes in 4 hours

beks73 [17]

Answer: 240 minutes

Step-by-step explanation:

Concept:

Here, we need to know the idea of unit conversion.

Unit conversion is the conversion between different units of measurement for the same quantity, typically through multiplicative conversion factors.

1 hour = 60 minutes

Solve:

1 hour = 60 minutes

4 hours = 4 × 60 = 240 minutes

Hope this helps!! :)

Please let me know if you have any questions

4 0

3 years ago

Daisy's mom is 4 times as old as she.The sum of their ages 6 years ago was 28.How is her mother now?

Delvig [45]

Answer:

Step-by-step explanation:

Daisy's mom is 4 times as old as she.

m = 4d

The sum of their ages 6 years ago was 28.

(m - 6) + (d - 6) = 28

Substitute for m = 4d

(4d - 6) + (d - 6) = 28

Combine like terms

5d - 12 = 28

5d = 40

Divide by 5

d = 8

m = 4d

m = 4 * 8

m = 32

7 0

2 years ago

A hose with a larger diameter working alone can fill a swimming pool in 9 hours.A hose with a smaller diameter working alone can

Arte-miy333 [17]

The large hose fills 1 pool in 9 hours written as 1/9

The small hose fills 1 pool in 18 hours, written as 1/18

Now you have 1/9 + 1/18 = 1/x ( x is the unknown time for both hoses).

rewrite 1/9 with a common denominator as 1/18:

1/9 = 2/18

Now you have 2/18 + 1/18 = 1/x

Add the left side:

2/18 + 1/18 = 3/18

Now you have 3/18 = 1/x

Cross Multiply:

3x = 18

Divide both sides by 3"

x = 18/3

X = 6

It will take both hoses 6 hours.

8 0

3 years ago

HELP ASAP! BRAINLIEST!

sammy [17]

26+12+7(2)= 38+14=52

8 0

3 years ago

Read 2 more answers

Alex is 12 years older than George. Carl is Three times older than Alex The sum of their ages is 68 Find the ratio of George’s a

earnstyle [38]

Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

Solution:

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

Alex is 12 years older than George

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

Carl is Three times older than Alex

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

The sum of their ages is 68

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

Substitute eqn 1 and eqn 2 in eqn 3

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

Substitute a = 16 in eqn 2

c = 3(16) = 48

c = 48

Substitute a = 16 in eqn 1

g = 16 - 12 = 4

g = 4

Find the ratio of George’s age to Carl’s age to Alex’s age

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

6 0

3 years ago