Let <em>f(x)</em> = (<em>x</em> ² - 1)³. Find the critical points of <em>f</em> in the interval [-1, 2]:
<em>f '(x)</em> = 3 (<em>x</em> ² - 1)² (2<em>x</em>) = 6<em>x</em> (<em>x </em>² - 1)² = 0
6<em>x</em> = 0 <u>or</u> (<em>x</em> ² - 1)² = 0
<em>x</em> = 0 <u>or</u> <em>x</em> ² = 1
<em>x</em> = 0 <u>or</u> <em>x</em> = 1 <u>or</u> <em>x</em> = -1
Check the value of <em>f</em> at each of these critical points, as well as the endpoints of the given domain:
<em>f</em> (-1) = 0
<em>f</em> (0) = -1
<em>f</em> (1) = 0
<em>f</em> (2) = 27
So max{<em>f(x)</em> | -1 ≤ <em>x </em>≤ 2} = 27.
Answer:
you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points
3.75 is how much each pond of candy cost
Increased just means +
10739 is the sum
Answer:
Overshoot.
Step-by-step explanation:
Let us know the meaning of given words.
Logistic growth occurs when population reaches carrying capacity of its environment. It does not surpass carrying capacity.
When population surpasses carrying capacity of its environment then a crash or a die-off happens, which causes a decline in population density. This crash or die off is known as collapse. The consequences of overshoot is known as collapse.
In population dynamics overshoot occurs when a population surpasses its carrying capacity. Overshoot is a temporary condition.
Therefore, from above explanation we can see that overshoot is the correct answer for the given phenomenon.
