A rocket booster initially applies 10,000 N of force to a 1,000.0 kg rocket causing it to accelerate at 10.0 m/s2. Ten minutes l
ater, the rocket booster is released and it falls through the atmosphere.
The mass of the rocket is now 760.0 kg and its acceleration is 7.0 m/s2. How much force is now being applied to the rocket?
The mass of the rocket is now 760.0 kg and its acceleration is 7.0 m/s2. How much force is now being applied to the rocket?
1 answer:
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Answer:
= 403
Step-by-step explanation:
the sum to n terms of an arithmetic series is
=
(a + l) ← a is the first term and l the last term
here a = - 5 and l = 67 , then
=
(- 5 + 67) = 6.5 × 62 = 403
Answer:
FC = 27, QC = 18
Step-by-step explanation:
The centroid Q is the way along CF , therefore, QF is half as long as CQ
Given FQ = 9, then
QC = 2 × 9 = 18
FC = FQ + QC = 9 + 18 = 27