Question

The product of 5 and the cube of x, increase by the difference of 6 and x3

Answer 1

Answer:

$4x^{3} +6$

Step-by-step explanation:

• The product of 5 and the cube of x

$5*x^3\\\\=5x^3$

• the difference of 6 and x^3

$6-x^3$

I understand as increase as sum so

$(5x^3)+(6-x^3)\\\\5x^3+6-x^3\\\\(5-1)x^3+6\\\\4x^3+6$