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Nikolay [14]
2 years ago
15

The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

the car be worth each of the following amounts?
(a) $8000
(b) $6000
(c) $1000
- The car will be worth $8000 after years.
(Type an integer or a decimal rounded to the nearest tenth as needed.)
Mathematics
1 answer:
lakkis [162]2 years ago
5 0

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

V(t) = 14651(0.81)^{t}

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

V(t) = 14651(0.81)^{t}

(0.81)^t = \frac{V(t)}{14651}

\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}

t\log{(0.81)} = \log{(\frac{V(t)}{14651})}

t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}

(a) $8000

V(t) = 8000

t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7

The car will be worth $1000 after 12.7 years.

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