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viktelen [127]
2 years ago
12

600 is how many times as much as 20?

Mathematics
1 answer:
Montano1993 [528]2 years ago
3 0

The value 600 is 30 times as much as 20

<h3>Ratio and proportion</h3>

Ratio are written in terms of fractions. The expression 600 is how many times as much as 20 can be written as;

600 = x *20

where x is the required value or factor

20x = 600

Divide both sides by 20

20x/20 = 600/20

x = 30

Hence the value 600 is 30 times as much as 20

Learn more on ratio and proportion here: brainly.com/question/19994681

#SPJ1

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f(t)=h=-16t^2+20t+6&#10;&#10;

a=-16, b=20, c =6

Δ=b^2-4ac=20^2-4*(-16)*6=400+384=784

\sqrt{Δ}=\sqrt{784}=28

max:

p=-\frac{b}{2a}=-\frac{20}{-32}=\frac{20}{32}=\frac{5}{8}

max heigh: h=-16(\frac{5}{8})^2+20*\frac{5}{8}+6=-16\frac{25}{64}+\frac{100}{8}+6

h=-\frac{25}{4}+\frac{50}{4}+6=\frac{-25+50+24}{4}=\frac{49}{4}

h=\frac{49}{4} at t=\frac{5}{8}s


will fall down at t:

t=\frac{-20-28}{-32}=\frac{-48}{-32}=\frac{3}{2}=1.5

t=1.5s

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Read 2 more answers
Will give brainiest algebra 2
mars1129 [50]

The sum of squares of numbers is: 13

Step-by-step explanation:

Let x and y be two numbers

Then,

Difference of the squares of the numbers will be:

x^2-y^2

Product will be:

xy

Given identity is:

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Given values are:

Difference of the squares of the numbers=x^2-y^2=5

Product of numbers = xy = 6

Putting the values in the identity

(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169

As we have to only find x^2+y^2

Taking square root on both sides

\sqrt{(x^2+y^2)^2}=\sqrt{169}\\x^2+y^2=13

The sum of squares of numbers is: 13

Keywords: Identities

Learn more about identities at:

  • brainly.com/question/8902155
  • brainly.com/question/8955867

#LearnwithBrainly

7 0
3 years ago
Solve the proportion of 2/v = 4/6
dsp73
\dfrac{2}{v} =  \dfrac{4}{6}

Cross multiply:
4v = 12

Divide both sides by 4:
v = 3
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3 years ago
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