Answer:
Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Explanation:
Lowest four digit positive integer = 1000
Highest four digit positive integer less than 4000 = 3999
We know that multiples of 5 end with 0 or 5 in their last digit.
So, lowest four digit positive integer which is a multiple of 5 = 1000
Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.
So, the numbers goes like,
1000, 1005, 1010 .....................................................3990, 3995
These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.
An = a + (n-1)d
3995 = 1000 + (n-1)x 5
(n-1) x 5 = 2995
(n-1) = 599
n = 600
So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Answer:
We simplify the equation to the form, which is simple to understand
5x+15=4x-12
We move all terms containing x to the left and all other terms to the right.
+5x-4x=-12-15
We simplify left and right side of the equation.
+1x=-27
then divide both sides of the equation by 1 to get x.
x=-27
Answer:
it would be 21
the only difference is that one is a negative and the other is a positive. The absolute value is the distance the number is from 0 on the number line.
hope i helped :)
Answer:
yes
Step-by-step explanation:
they are all equivalent because they all equal 0.9
9/10 = 90/100 = 0.9
all percentages can be converted to fraction by putting them over a hundred
90% = 90/100 = 0.9
0.9 obviously = 0.9
