Question

In the equation square root n+5-square root n-10=1 the value of n is

Answer 1

Answer:

the value of n is 59

Step-by-step explanation:

plato says it was right (:

Answer 2

square root n+5-square root n-10=1

$\sqrt{n+5} - \sqrt{n-10} =1$

add sqrt(n-10) on both sides

$\sqrt{n+5} =1+ \sqrt{n-10}$

To remove square root we take square on both sides

$(\sqrt{n+5})^2 =(1+ \sqrt{n-10})^2$

$n+5=(1+ 2\sqrt{n-10} +n -10)$

$n+5=2\sqrt{n-10} +n -9$

Subtract n  and add 9 on both sides

$14=2\sqrt{n-10}$

Now we divide both sides by 2

$7=\sqrt{n-10}$

Take square on both sides

 +-49= n - 10

49 = n-10   and -49 = n - 10

Add 10 on both sides

n= 59   and n = -39

Now we verify both solutions

When n = -39 we will get negative under the square root . that is complex so we ignore n=-39

n = 59 is our solution